3x(2x+5)=4(x^2+15)+2x^2

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Solution for 3x(2x+5)=4(x^2+15)+2x^2 equation: 


Simplifying
3x(2x + 5) = 4(x2 + 15) + 2x2

Reorder the terms:
3x(5 + 2x) = 4(x2 + 15) + 2x2
(5 * 3x + 2x * 3x) = 4(x2 + 15) + 2x2
(15x + 6x2) = 4(x2 + 15) + 2x2

Reorder the terms:
15x + 6x2 = 4(15 + x2) + 2x2
15x + 6x2 = (15 * 4 + x2 * 4) + 2x2
15x + 6x2 = (60 + 4x2) + 2x2

Combine like terms: 4x2 + 2x2 = 6x2
15x + 6x2 = 60 + 6x2

Add '-6x2' to each side of the equation.
15x + 6x2 + -6x2 = 60 + 6x2 + -6x2

Combine like terms: 6x2 + -6x2 = 0
15x + 0 = 60 + 6x2 + -6x2
15x = 60 + 6x2 + -6x2

Combine like terms: 6x2 + -6x2 = 0
15x = 60 + 0
15x = 60

Solving
15x = 60

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '15'.
x = 4

Simplifying
x = 4

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